(x/6)-(1/3)=(4x^2)+2x-3

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Solution for (x/6)-(1/3)=(4x^2)+2x-3 equation: 



(x/6)-(1/3)=(4x^2)+2x-3

We move all terms to the left:

(x/6)-(1/3)-((4x^2)+2x-3)=0

We add all the numbers together, and all the variables

(+x/6)-(4x^2+2x-3)-(+1/3)=0

We get rid of parentheses

-4x^2+x/6-2x+3-1/3=0

We calculate fractions

There is no solution for this equation

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